Offday Fun
A thoroughly honest game-show host has placed a car behind one of three doors. There is a goat behind each of the other doors. You have no prior knowledge that allows you to distinguish among the doors. "First you point toward a door," he says. "Then I'll open one of the other doors to reveal a goat. After I've shown you the goat, you make your final choice whether to stick with your initial choice of doors, or to switch to the remaining door. You win whatever is behind the door." You begin by pointing to door number 1. The host shows you that door number 3 has a goat.
Do the player's chances of getting the car increase by switching to Door 2?
NOTE: Explanation - http://en.wikipedia.org/wiki/Monty_hall_problem/
("Do you see what happens, Larry?")
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11 comments
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why?
by shaftr on
Apr 3, 2007 2:59 PM CDT
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your odds are 2/3 if you switch
by larry on
Apr 3, 2007 3:04 PM CDT
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still a fun exercise
by larry on
Apr 3, 2007 3:06 PM CDT
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doesn't matter.
by Toonderstrook on
Apr 3, 2007 2:58 PM CDT
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but
by Toonderstrook on
Apr 3, 2007 3:12 PM CDT
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Right...
by The Jerry Royster Experience on
Apr 3, 2007 3:20 PM CDT
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yeah, it's clear
by larry on
Apr 3, 2007 3:25 PM CDT
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It also depends on the assumption...
But it's really a matter of how you understand the question.
by The Jerry Royster Experience on
Apr 3, 2007 3:37 PM CDT
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One interesting way
If you employ the switching method everytime, then the only way you will get it wrong is if you initially choose the right door (33% chance). If you initially choose either of the wrong doors (67% chance), the other wrong door is revealed, and you will always switch over to the correct door.
I miss the days when the problems I had to face on daily basis were mathematical in nature and not, "How can I please the client?" (Also being able to watch Sox day games was nice).
by CatBrains on
Apr 4, 2007 10:04 AM CDT
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